Java: 如何去除对象数组中的重复元素？

java对象数组去重；

• 将原数组插入到新数组的时候，将插入的对象和新数组中的已插入对象进行比较，若不相同，则插入到新的数组中；
• 使用hashSet进行对象的去重（需要将list中对象的hasCode()、equals()方法进行重写，然后放到set集合中）

package com.arraySort;

import java.util.ArrayList;
import java.util.List;
import java.util.Objects;
import java.util.stream.Collectors;

public class DistinctPerson {

    private String name;

    private int score;

    public DistinctPerson(int score, String name) {
        super();
        this.name = name;
        this.score = score;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public int getScore() {
        return score;
    }

    public void setScore(int score) {
        this.score = score;
    }

    /**
     * 当name相同，就认定两个对象相等
     *
     * @param o
     * @return
     */
    @Override
    public boolean equals(Object o) {
        if (this == o) {
            return true;
        }
        if (o == null || getClass() != o.getClass()) {
            return false;
        }
        DistinctPerson that = (DistinctPerson) o;
        return Objects.equals(name, that.name);
    }

    /**
     * 仅使用name字段的值来生成hashcode；
     *
     * @return
     */
    @Override
    public int hashCode() {
        return Objects.hash(name);
    }

    @Override
    public String toString() {
        return "DistinctPerson{" +
                "name='" + name + '\'' +
                ", score=" + score +
                '}';
    }

    private static List<DistinctPerson> initList() {
        List<DistinctPerson> distinctPeople = new ArrayList<DistinctPerson>();
        distinctPeople.add(new DistinctPerson(980, "M1"));
        distinctPeople.add(new DistinctPerson(34, "M2"));
        distinctPeople.add(new DistinctPerson(12, "M3"));
        distinctPeople.add(new DistinctPerson(65, "M4"));
        distinctPeople.add(new DistinctPerson(12, "M5"));
        distinctPeople.add(new DistinctPerson(33, "M6"));
        distinctPeople.add(new DistinctPerson(90, "M7"));
        distinctPeople.add(new DistinctPerson(123, "M8"));
        distinctPeople.add(new DistinctPerson(124, "M8"));
        return distinctPeople;
    }

    private static void pirntList(String title, List<DistinctPerson> distinctPeople) {
        System.out.println("==============" + title + "=================");
        for (DistinctPerson distinctPerson : distinctPeople) {
            System.out.println(distinctPerson.toString());
        }
    }

    public static void main(String[] args) {

//       方法一：将原数组插入到新数组的时候，将插入的对象和新数组中的已插入对象进行比较，若不相同，则插入到新的数组中；
        List<DistinctPerson> distinctPeople = initList();
        List<DistinctPerson> newDistinctPeople = new ArrayList<>();
        distinctPeople.forEach(t -> {
            //anyMatch表示有一个匹配就返回true;
            boolean match = newDistinctPeople.stream().anyMatch(u -> t.getName().equals(u.getName()));
            if (!match) {
                newDistinctPeople.add(t);
            }
        });

        pirntList("方法一", newDistinctPeople);


        /**
         方法二：使用hashSet进行对象的去重（需要将list中对象的hasCode()、equals()方法进行重写，然后放到set集合中）
         * 若对象中的equals方法的返回值为true，hashCode方法的返回值必定是相同的；
         */
        distinctPeople = initList();
        distinctPeople = distinctPeople.parallelStream().distinct().collect(Collectors.toList());
        pirntList("方法二", distinctPeople);
    }
}

运行结果如下：

==============方法一=================
DistinctPerson{name='M1', score=980}
DistinctPerson{name='M2', score=34}
DistinctPerson{name='M3', score=12}
DistinctPerson{name='M4', score=65}
DistinctPerson{name='M5', score=12}
DistinctPerson{name='M6', score=33}
DistinctPerson{name='M7', score=90}
DistinctPerson{name='M8', score=123}
==============方法二=================
DistinctPerson{name='M1', score=980}
DistinctPerson{name='M2', score=34}
DistinctPerson{name='M3', score=12}
DistinctPerson{name='M4', score=65}
DistinctPerson{name='M5', score=12}
DistinctPerson{name='M6', score=33}
DistinctPerson{name='M7', score=90}
DistinctPerson{name='M8', score=123}